Lua - decodeURI (luvit)
decodeuricomponent, encodeuricomponent, lua, urldecode
Solution
This is trivial to do yourself in Lua if you understand the URI percent-encoded format. Each `%XX` substring represents UTF-8 data encoded with a `%` prefix and a hexadecimal octet.
local decodeURI
do
local char, gsub, tonumber = string.char, string.gsub, tonumber
local function _(hex) return char(tonumber(hex, 16)) end
function decodeURI(s)
s = gsub(s, '%%(%x%x)', _)
return s
end
end
print(decodeURI('%D0%BF%D1%80%D0%B8%D0%B2%D0%B5%D1%82'))
Problem
I would like to use `decodeURI` or `decodeURIComponent` as in JavaScript in my Lua (Luvit) project. JavaScript: ``` decodeURI('%D0%BF%D1%80%D0%B8%D0%B2%D0%B5%D1%82') // result: привет ``` Luvit: ``` require('querystring').urldecode('%D0%BF%D1%80%D0%B8%D0%B2%D0%B5%D1%82') -- result: '%D0%BF%D1%80%D0%B8%D0%B2%D0%B5%D1%82' ```