how to urldecode a request_uri string in Lua

lua, nginx

Solution

The decoded URI can be found in `ngx.var.uri`. It does not contain the query string, if you need it see `ngx.var.query_string`.

EDIT: if you cannot use this, here is a simple way to unescape a URL in Lua.

local hex_to_char = function(x)
  return string.char(tonumber(x, 16))
end

local unescape = function(url)
  return url:gsub("%%(%x%x)", hex_to_char)
end

Example usage:

local url = "/test/some%20string?foo=bar"
print(unescape(url)) -- /test/some string?foo=bar

But you should probably split the query string before using it.

Problem

When I use `ngx.var.request_uri` I'm getting back a string that contains %20 in place of spaces. Is there a urldecode() function or similar to decode my string?

Original source