Why is nextLine() returning an empty string?
java
Solution
`nextInt` doesn't read the following new-line character, so the first `nextLine` (which returns the rest of the current line) will always return an empty string.
This should work:
numberRegisters = readInput.nextInt();
readInput.nextLine();
while (!(line = readInput.nextLine()).isEmpty()) {
System.out.println(line + "<");
}
But my advice is not to mix `nextLine` with `nextInt` / `nextDouble` / `next` / etc. because anyone trying to maintain the code (yourself included) may not be aware of, or have forgotten, the above, so may be somewhat confused by the above code.
So I suggest:
numberRegisters = Integer.parseInt(readInput.nextLine());
while (!(line = readInput.nextLine()).isEmpty()) {
System.out.println(line + "<");
}
Problem
This is probably one of the easiest things but I'm not seeing what I'm doing wrong. My input consist of one first line with a number (the number of lines to read), a bunch of lines with data and a final line only with \n. I should process this input and after the last line, do some work. I have this input: ``` 5 test1 test2 test3 test4 test5 /*this is a \n*/ ``` And for reading the input I have this code. ``` int numberRegisters; String line; Scanner readInput = new Scanner(System.in); numberRegisters = readInput.nextInt(); while (!(line = readInput.nextLine()).isEmpty()) { System.out.println(line + "<"); } ``` My question is why I'm not printing anything? Program reads the first line and then does nothing.