Scanner is skipping nextLine() after using next() or nextFoo()?
io, java, java.util.scanner
Solution
That's because the `Scanner.nextInt` method does not read the newline character in your input created by hitting "Enter," and so the call to `Scanner.nextLine` returns after reading that newline.
You will encounter the similar behaviour when you use `Scanner.nextLine` after `Scanner.next()` or any `Scanner.nextFoo` method (except `nextLine` itself).
Workaround:
Either put a `Scanner.nextLine` call after each `Scanner.nextInt` or `Scanner.nextFoo` to consume rest of that line including newline
int option = input.nextInt();
input.nextLine(); // Consume newline left-over
String str1 = input.nextLine();
Or, even better, read the input through `Scanner.nextLine` and convert your input to the proper format you need. For example, you may convert to an integer using `Integer.parseInt(String)` method.
int option = 0;
try {
option = Integer.parseInt(input.nextLine());
} catch (NumberFormatException e) {
e.printStackTrace();
}
String str1 = input.nextLine();
Problem
I am using the `Scanner` methods `nextInt()` and `nextLine()` for reading input. It looks like this: ``` System.out.println("Enter numerical value"); int option; option = input.nextInt(); // Read numerical value from input System.out.println("Enter 1st string"); String string1 = input.nextLine(); // Read 1st string (this is skipped) System.out.println("Enter 2nd string"); String string2 = input.nextLine(); // Read 2nd string (this appears right after reading numerical value) ``` The problem is that after entering the numerical value, the first `input.nextLine()` is skipped and the second `input.nextLine()` is executed, so that my output looks like this: ``` Enter numerical value 3 // This is my input Enter 1st string // The program is supposed to stop here and wait for my input, but is skipped Enter 2nd string // ...and this line is executed and waits for my input ``` I tested my application and it looks like the problem lies in using `input.nextInt()`. If I delete it, then both `string1 = input.nextLine()` and `string2 = input.nextLine()` are executed as I want them to be.