How to sort a Python dictionary by value?

python, sorting

Solution

Dictionaries can't be sorted as such, but you can sort their contents:

sorted(a_dict.items(), key=lambda (k, (v1, v2)): v2)
sorted(a_dict.items(), key=lambda item: item[1][1])    # Python 3

You can put the results into a `collections.OrderedDict` (since 2.7):

OrderedDict(sorted(a_dict.items(), key=lambda (k, (v1, v2)): v2))
OrderedDict(sorted(a_dict.items(), key=lambda item: item[1][1])    # Python 3

Problem

Possible Duplicate: In Python how do I sort a list of dictionaries by values of the dictionary? Sorting Python dictionary based on nested dictionary values I have dictionary of the form as mentioned below: ``` a_dict = { 'e': (1, 100), 'a': (2, 3) } ``` I am unable to sort it by the second element of the tuple. The resultant dictionary will appear as below: ``` a_dict = { 'a': (2, 3), 'e': (1, 100) } ```

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