How to sort a list of dictionaries by a value of the dictionary in Python?
data-structures, dictionary, list, python, sorting
Solution
The `sorted()` function takes a `key=` parameter
newlist = sorted(list_to_be_sorted, key=lambda d: d['name'])
Alternatively, you can use `operator.itemgetter` instead of defining the function yourself
from operator import itemgetter
newlist = sorted(list_to_be_sorted, key=itemgetter('name'))
For completeness, add `reverse=True` to sort in descending order
newlist = sorted(list_to_be_sorted, key=itemgetter('name'), reverse=True)
Problem
How do I sort a list of dictionaries by a specific key's value? Given: ``` [{'name': 'Homer', 'age': 39}, {'name': 'Bart', 'age': 10}] ``` When sorted by `name`, it should become: ``` [{'name': 'Bart', 'age': 10}, {'name': 'Homer', 'age': 39}] ```