What decides the sizeof an integer?
64-bit, c, compiler-construction, sizeof
Solution
Taken from http://en.wikipedia.org/wiki/64-bit (under `64-bit data models`)
There are various models, Microsoft decided that `sizeof(int) == 4`, some (a few) others didn't.
HAL Computer Systems port of Solaris to SPARC64 and Unicos seem to be the only ones where `sizeof(int) == 8`. They are called ILP64 and SILP64 models.
The true "war" was for `sizeof(long)`, where Microsoft decided for `sizeof(long) == 4` (LLP64) while nearly everyone else decided for `sizeof(long) == 8` (LP64).
Note that in truth it's the compiler that "decides" which model to use, but as written in the wiki
Note that a programming model is a choice made on a per-compiler basis, and several can coexist on the same OS. However, the programming model chosen as the primary model for the OS API typically dominates.
Problem
`sizeof(int)` shows 4 on my `Dev Cpp` even though its running on a 64 bit machine. Why doesn't it consider the underlying HW and show 8 instead? Also, if I compiling environment also changes to 64 bit ( Does a `64 bit compiler` makes sense in the first place?! ), would size of int change then? Are there any standards which decide this?