How to get a slice from "arguments"

javascript

Solution

Meddling with array functions is not actually necessary.

Using rest parameter syntax `...rest` is cleaner and more convenient.

Example

function argumentTest(first, ...rest) {
  console.log("First arg:" + first);

  // loop through the rest of the parameters
  for (let arg of rest) {
    console.log("- " + arg);
  }
}

// call your function with any number of arguments
argumentTest("first arg", "#2", "more arguments", "this is not an argument but a contradiction");

...Rest

- See the example Fiddle

- See MDN Documentation page

Problem

All you know that `arguments` is a special object that holds all the arguments passed to the function. And as long as it is not an array - you cannot use something like `arguments.slice(1)`. So the question - how to slice everything but first element from `arguments`? UPD: seems like there is no way without converting it to an array with ``` var args = Array.prototype.slice.call(arguments); ``` If someone posts another solution it would be great, if not - I'll check the first one with the line above as an answer.

Original source