Determine if a type is an STL container at compile time
c++, stl, template-meta-programming, templates
Solution
First, you define your primary template, which will have a member which is false in the default case:
template <typename T>
struct is_cont {
static const bool value = false;
};
Then you will define partial specializations for your container types which have a value of true instead:
template <typename T,typename Alloc>
struct is_cont<std::vector<T,Alloc> > {
static const bool value = true;
};
Then for a type X that you want to check, use it like
if (is_cont<X>::value) { ... }
Problem
I would like to write a template that will determine if a type is an stl container at compile time. I've got the following bit of code: ``` struct is_cont{}; struct not_cont{}; template <typename T> struct is_cont { typedef not_cont result_t; }; ``` but I'm not sure how to create the necessary specializations for `std::vector<T,Alloc>, deque<T,Alloc>, set<T,Alloc,Comp>` etc...