Resources.openRawResource() issue Android

android, java

Solution

Yes, you should be able to use `openRawResource` to copy a binary across from your raw resource folder to the device.

Based on the example code in the API demos (content/ReadAsset), you should be able to use a variation of the following code snippet to read the db file data.

InputStream ins = getResources().openRawResource(R.raw.my_db_file);
ByteArrayOutputStream outputStream=new ByteArrayOutputStream();
int size = 0;
// Read the entire resource into a local byte buffer.
byte[] buffer = new byte[1024];
while((size=ins.read(buffer,0,1024))>=0){
  outputStream.write(buffer,0,size);
}
ins.close();
buffer=outputStream.toByteArray();

A copy of your file should now exist in `buffer`, so you can use a `FileOutputStream` to save the buffer to a new file.

FileOutputStream fos = new FileOutputStream("mycopy.db");
fos.write(buffer);
fos.close();

Problem

I have a database file in `res/raw/` folder. I am calling `Resources.openRawResource()` with the file name as `R.raw.FileName` and I get an input stream, but I have an another database file in device, so to copy the contents of that db to the device db I use: ``` BufferedInputStream bi = new BufferedInputStream(is); ``` and FileOutputStream, but I get an exception that database file is corrupted. How can I proceed? I try to read the file using `File` and `FileInputStream` and the path as `/res/raw/fileName`, but that also doesn't work.

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