Checking from shell script if a directory contains files
bash, shell, unix
Solution
The solutions so far use `ls`. Here's an all bash solution:
#!/bin/bash
shopt -s nullglob dotglob # To include hidden files
files=(/some/dir/*)
if [ ${#files[@]} -gt 0 ]; then echo "huzzah"; fi
Problem
From a shell script, how do I check if a directory contains files? Something similar to this ``` if [ -e /some/dir/* ]; then echo "huzzah"; fi; ``` but which works if the directory contains one or several files (the above one only works with exactly 0 or 1 files).