Enumerate members of a structure?
c, c++, enumeration
Solution
To state the obvious, there is no reflection in C or C++. Hence no reliable way of enumerating member variables (by default).
If you have control over your data structure, you could try a `std::vector<boost::any>` or a `std::map<std::string, boost::any>` then add all your member variables to the vector/map.
Of course, this means all your variables will likely be on the heap so there will be a performance hit with this approach. With the std::map approach, it means that you would have a kind of "poor man's" reflection.
Problem
Is there a way to enumerate the members of a structure (struct | class) in C++ or C? I need to get the member name, type, and value. I've used the following sample code before on a small project where the variables were globally scoped. The problem I have now is that a set of values need to be copied from the GUI to an object, file, and VM environment. I could create another "poor man’s" reflection system or hopefully something better that I haven't thought of yet. Does anyone have any thoughts? EDIT: I know C++ doesn't have reflection. ``` union variant_t { unsigned int ui; int i; double d; char* s; }; struct pub_values_t { const char* name; union variant_t* addr; char type; // 'I' is int; 'U' is unsigned int; 'D' is double; 'S' is string }; #define pub_v(n,t) #n,(union variant_t*)&n,t struct pub_values_t pub_values[] = { pub_v(somemember, 'D'), pub_v(somemember2, 'D'), pub_v(somemember3, 'U'), ... }; const int no_of_pub_vs = sizeof(pub_values) / sizeof(struct pub_values_t); ```