How to generate a random string in Ruby
passwords, random, ruby
Solution
(0...8).map { (65 + rand(26)).chr }.join
I spend too much time golfing.
(0...50).map { ('a'..'z').to_a[rand(26)] }.join
And a last one that's even more confusing, but more flexible and wastes fewer cycles:
o = [('a'..'z'), ('A'..'Z')].map(&:to_a).flatten
string = (0...50).map { o[rand(o.length)] }.join
If you want to generate some random text then use the following:
50.times.map { (0...(rand(10))).map { ('a'..'z').to_a[rand(26)] }.join }.join(" ")
this code generates 50 random word string with words length less than 10 characters and then join with space
Problem
I'm currently generating an 8-character pseudo-random uppercase string for "A" .. "Z": ``` value = ""; 8.times{value << (65 + rand(25)).chr} ``` but it doesn't look clean, and it can't be passed as an argument since it isn't a single statement. To get a mixed-case string "a" .. "z" plus "A" .. "Z", I changed it to: ``` value = ""; 8.times{value << ((rand(2)==1?65:97) + rand(25)).chr} ``` but it looks like trash. Does anyone have a better method?