Super in Backbone
backbone.js, inheritance, javascript
Solution
You'll want to use:
Backbone.Model.prototype.clone.call(this);
This will call the original `clone()` method from `Backbone.Model` with the context of `this`(The current model).
From Backbone docs:
Brief aside on super: JavaScript does not provide a simple way to call super — the function of the same name defined higher on the prototype chain. If you override a core function like set, or save, and you want to invoke the parent object's implementation, you'll have to explicitly call it.
var Note = Backbone.Model.extend({
set: function(attributes, options) {
Backbone.Model.prototype.set.apply(this, arguments);
...
}
});
Problem
When I override the `clone()` method of a `Backbone.Model`, is there a way to call this overriden method from my implantation? Something like this: ``` var MyModel = Backbone.Model.extend({ clone: function(){ super.clone();//calling the original clone method } }) ```