Point-free style and using $
haskell, pointfree
Solution
You can use this combinator: (The colon hints that two arguments follow)
(.:) :: (c -> d) -> (a -> b -> c) -> a -> b -> d
(.:) = (.) . (.)
It allows you to get rid of the `n`:
time = concat .: replicate
Problem
How does one combine using `$` and point-free style? A clear example is the following utility function: ``` times :: Int -> [a] -> [a] times n xs = concat $ replicate n xs ``` Just writing `concat $ replicate` produces an error, similarly you can't write `concat . replicate` either because `concat` expects a value and not a function. So how would you turn the above function into point-free style?