Drawing rectangle between two points with arbitrary width
2d, math, opengl, qt
Solution
Calculate a vector between start and end points
V.X := Point2.X - Point1.X;
V.Y := Point2.Y - Point1.Y;
Then calculate a perpendicular to it (just swap X and Y coordinates)
P.X := V.Y; //Use separate variable otherwise you overwrite X coordinate here
P.Y := -V.X; //Flip the sign of either the X or Y (edit by adam.wulf)
Normalize that perpendicular
Length = sqrt(P.X * P.X + P.Y * P.Y); //Thats length of perpendicular
N.X = P.X / Length;
N.Y = P.Y / Length; //Now N is normalized perpendicular
Calculate 4 points that form a rectangle by adding normalized perpendicular and multiplying it by half of the desired width
R1.X := Point1.X + N.X * Width / 2;
R1.Y := Point1.Y + N.Y * Width / 2;
R2.X := Point1.X - N.X * Width / 2;
R2.Y := Point1.Y - N.Y * Width / 2;
R3.X := Point2.X + N.X * Width / 2;
R3.Y := Point2.Y + N.Y * Width / 2;
R4.X := Point2.X - N.X * Width / 2;
R4.Y := Point2.Y - N.Y * Width / 2;
Draw rectangle using these 4 points.
Here's the picture:
EDIT: To answer the comments: If X and Y are the same then the line is exactly diagonal and perpendicular to a diagonal is a diagonal. Normalization is a method of making a length to equal to 1, so that the width of your line in this example will not depend on perpendiculars length (which is equal to lines length here).
Problem
I'm trying to draw a line between two (2D) points when the user swipes their finger across a touch screen. To do this, I plan on drawing a rectangle on every touch update between the X and Y of the previous touch update and the X and Y of the latest touch update. This should create a continuous and solid line as the user swipes their finger across the screen. However, I would also like this line to have an arbitrary width. My question is, how should I go about calculating the coordinates I need for each rectangle (x1, y1, x2, y2)? -- Also: if anyone has any information on how I could then go about applying anti-aliasing to this line it'd be a massive help.