C/C++: casting away volatile considered harmful?

c, c++, volatile

Solution

If the variable is declared `volatile` then it is undefined behaviour to cast away the `volatile`, just as it is undefined behaviour to cast away the `const` from a variable declared `const`. See Annex J.2 of the C Standard:

The behavior is undefined in the following circumstances:

...

— An attempt is made to modify an object defined with a const-qualified type through use of an lvalue with non-const-qualified type (6.7.3).

— An attempt is made to refer to an object defined with a volatile-qualified type through use of an lvalue with non-volatile-qualified type (6.7.3).

If, however, you just have a `volatile` pointer or a `volatile` reference to a non-`volatile` variable then you can freely cast away `volatile`.

volatile int i=0;
int j=0;

volatile int* pvi=&i; // ok
volatile int* pvj=&j; // ok can take a volatile pointer to a non-volatile object

int* pi=const_cast<int*>(pvi); // Danger Will Robinson! casting away true volatile
int* pj=const_cast<volatile int*>(pvj); // OK
*pi=3; // undefined behaviour, non-volatile access to volatile variable
*pj=3; // OK, j is not volatile

Problem

(related to this question Is It Safe to Cast Away volatile?, but not quite the same, as that question relates to a specific instance) Is there ever a case where casting away `volatile` is not considered a dangerous practice? (one particular example: if there is a function declared ``` void foo(long *pl); ``` and I have to implement ``` void bar(volatile long *pl); ``` with part of my implementation requiring bar() to call foo(pl), then it seems like I can't get this to work as is, because the assumptions made by the compilation of foo() and the compilation of the caller of bar() are incompatible.) As a corollary, if I have a `volatile` variable v, and I want to call `foo(&v)` with someone else's function `void foo(long *pl)`, and that person tells me it's safe, I can just cast the pointer before the call, my instinct is to tell them they're wrong because there's no way to guarantee that, and that they should change the declaration to `void foo(volatile long *pl)` if they want to support the use of volatile variables. Which one of us is correct?

Original source

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