How to avoid a Toast if there's one Toast already being shown
android, android-toast
Solution
I've tried a variety of things to do this. At first I tried using the `cancel()`, which had no effect for me (see also this answer).
With `setDuration(n)` I wasn't coming to anywhere either. It turned out by logging `getDuration()` that it carries a value of 0 (if `makeText()`'s parameter was `Toast.LENGTH_SHORT`) or 1 (if `makeText()`'s parameter was `Toast.LENGTH_LONG`).
Finally I tried to check if the toast's view `isShown()`. Of course it isn't if no toast is shown, but even more, it returns a fatal error in this case. So I needed to try and catch the error. Now, `isShown()` returns true if a toast is displayed. Utilizing `isShown()` I came up with the method:
/**
* <strong>public void showAToast (String st)</strong></br>
* this little method displays a toast on the screen.</br>
* it checks if a toast is currently visible</br>
* if so </br>
* ... it "sets" the new text</br>
* else</br>
* ... it "makes" the new text</br>
* and "shows" either or
* @param st the string to be toasted
*/
public void showAToast (String st){ //"Toast toast" is declared in the class
try{ toast.getView().isShown(); // true if visible
toast.setText(st);
} catch (Exception e) { // invisible if exception
toast = Toast.makeText(theContext, st, toastDuration);
}
toast.show(); //finally display it
}
Problem
I have several `SeekBar` and `onSeekBarProgressStop()`, I want to show a `Toast` message. But if on `SeekBar` I perform the action rapidly then UI thread somehow blocks and `Toast` message waits till UI thread is free. Now my concern is to avoid the new `Toast` message if the `Toast` message is already displaying. Or is their any condition by which we check that UI thread is currently free then I'll show the `Toast` message. I tried it in both way, by using `runOnUIThread()` and also creating new `Handler`.