Convert a matrix to a list of column-vectors
list, matrix, r
Solution
In the interests of skinning the cat, treat the array as a vector as if it had no dim attribute:
split(x, rep(1:ncol(x), each = nrow(x)))
Problem
Say you want to convert a matrix to a list, where each element of the list contains one column. `list()` or `as.list()` obviously won't work, and until now I use a hack using the behaviour of `tapply` : ``` x <- matrix(1:10, ncol = 2) tapply(x, rep(1:ncol(x), each = nrow(x)), function(i) i) ``` I'm not completely happy with this. Anybody knows a cleaner method I'm overlooking? (for making a list filled with the rows, the code can obviously be changed to : ``` tapply(x, rep(1:nrow(x), ncol(x)), function(i) i) ``` )