How do I translate an expression tree of one type to a different expression type?

c#, c#-4.0, expression-trees, lambda

Solution

Here's a visitor that does the job.

- it makes a copy of the parameter (since we'll need to create a new parameter and substitute all references of the old parameter for the new one)

- it walks the `.Body` of the tree, substituting the parameter, and switching any member-access against the old type to a like-named member on the new type

- it re-assembles a lambda using the parameter we invented earler

Code:

class TypeChangeVisitor : ExpressionVisitor
{
    private readonly Type from, to;
    private readonly Dictionary<Expression, Expression> substitutions;
    public TypeChangeVisitor(Type from, Type to, Dictionary<Expression, Expression> substitutions)
    {
        this.from = from;
        this.to = to;
        this.substitutions = substitutions;
    }
    public override Expression  Visit(Expression node)
    { // general substitutions (for example, parameter swaps)
        Expression found;
        if(substitutions != null && substitutions.TryGetValue(node, out found))
        {
            return found;
        }
        return base.Visit(node);
    }
    protected override Expression VisitMember(MemberExpression node)
    { // if we see x.Name on the old type, substitute for new type
        if (node.Member.DeclaringType == from)
        {
            return Expression.MakeMemberAccess(Visit(node.Expression),
                to.GetMember(node.Member.Name, node.Member.MemberType,
                BindingFlags.Instance | BindingFlags.Static | BindingFlags.Public | BindingFlags.NonPublic).Single());
        }
        return base.VisitMember(node);
    }
}
public class Program
{
    public static void Main()
    {
        Expression<Func<AnimalViewModel, bool>> predicate = x => x.Name == "abc";
        var switched = Translate<AnimalViewModel, Animal>(predicate);
    }
    public static Expression<Func<TTo, bool>> Translate<TFrom, TTo>(Expression<Func<TFrom, bool>> expression)
    {
        var param = Expression.Parameter(typeof(TTo), expression.Parameters[0].Name);
        var subst = new Dictionary<Expression, Expression> { { expression.Parameters[0], param } };
        var visitor = new TypeChangeVisitor(typeof(TFrom), typeof(TTo), subst);
        return Expression.Lambda<Func<TTo, bool>>(visitor.Visit(expression.Body), param);
    }
}

Note that if you have `x.Something.Name` you might need to be a bit more careful, but this should get you a reasonable way.

Problem

If I have two nearly identical classes `Animal` and `AnimalViewModel` and an expression tree related to the viewmodel, how can I translate it to `Animal`? ``` public class Animal { public string Species { get; set; } public string Name { get; set; } public string Sound { get; set; } } public class AnimalViewModel : ViewModelBase { public string Species { get; set; } public string Name { get; set; } public string Sound { get; set; } } ``` How can I translate an `Expression<Func<AnimalViewModel,bool>>` to `Expression<Func<Animal,bool>>`? ``` public static Expression<Func<Animal,bool>> Translate (Expression<Func<AnimalViewModel,bool>> expression) { // What goes here? I assume I have to traverse the tree somehow. } ```

Original source