How can I put multiple statements in one line?
python
Solution
Unfortunately, what you want is not possible with Python (which makes Python close to useless for command-line one-liner programs). Even explicit use of parentheses does not avoid the syntax exception. You can get away with a sequence of simple statements, separated by semicolon:
for i in range(10): print "foo"; print "bar"
But as soon as you add a construct that introduces an indented block (like `if`), you need the line break. Also,
for i in range(10): print "i equals 9" if i==9 else None
is legal and might approximate what you want.
If you are still determined to use one-liners, see the answer by elecprog.
As for the `try ... except` thing: It would be totally useless without the `except`. `try` says "I want to run this code, but it might throw an exception". If you don't care about the exception, leave out the `try`. But as soon as you put it in, you're saying "I want to handle a potential exception". The `pass` then says you wish to not handle it specifically. But that means your code will continue running, which it wouldn't otherwise.
Problem
I know a little bit of comprehensions in Python, but they seem very hard to 'read'. The way I see it, a comprehension might accomplish the same as the following code: ``` for i in range(10): if i == 9: print('i equals 9') ``` This code is much easier to read than how comprehensions currently work, but I've noticed you can’t have two `:`s in one line. This brings me to: Is there a way I can get the following example into one line? ``` try: if sam[0] != 'harry': print('hello', sam) except: pass ``` Something like this would be great: ``` try: if sam[0] != 'harry': print('hellp', sam) except:pass ``` But again I encounter the conflicting `:`s. I'd also love to know if there's a way to run `try` (or something like it) without `except`. It seems entirely pointless that I need to put `except:pass` in there. It’s a wasted line.