Why does this iterative list-growing code give IndexError: list assignment index out of range? How can I repeatedly add (append) elements to a list?

exception, list, python

Solution

`j` is an empty list, but you're attempting to write to element `[0]` in the first iteration, which doesn't exist yet.

Try the following instead, to add a new element to the end of the list:

for l in i:
    j.append(l)

Of course, you'd never do this in practice if all you wanted to do was to copy an existing list. You'd just do:

j = list(i)

Alternatively, if you wanted to use the Python list like an array in other languages, then you could pre-create a list with its elements set to a null value (`None` in the example below), and later, overwrite the values in specific positions:

i = [1, 2, 3, 5, 8, 13]
j = [None] * len(i)
#j == [None, None, None, None, None, None]
k = 0

for l in i:
   j[k] = l
   k += 1

The thing to realise is that a `list` object will not allow you to assign a value to an index that doesn't exist.

Problem

I tried writing some code like: ``` i = [1, 2, 3, 5, 8, 13] j = [] k = 0 for l in i: j[k] = l k += 1 ``` But I get an error message that says `IndexError: list assignment index out of range`, referring to the `j[k] = l` line of code. Why does this occur? How can I fix it?

Original source