Calling method using JavaScript prototype
javascript, overriding, prototype
Solution
I did not understand what exactly you're trying to do, but normally implementing object-specific behaviour is done along these lines:
function MyClass(name) {
this.name = name;
}
MyClass.prototype.doStuff = function() {
// generic behaviour
}
var myObj = new MyClass('foo');
var myObjSpecial = new MyClass('bar');
myObjSpecial.doStuff = function() {
// do specialised stuff
// how to call the generic implementation:
MyClass.prototype.doStuff.call(this /*, args...*/);
}
Problem
Is it possible to call the base method from a prototype method in JavaScript if it's been overridden? ``` MyClass = function(name){ this.name = name; this.do = function() { //do somthing } }; MyClass.prototype.do = function() { if (this.name === 'something') { //do something new } else { //CALL BASE METHOD } }; ```