Comma operator returns first value instead of second in argument list?
comma-operator, javascript, operators
Solution
In the context of a function call, the comma is used to separate parameters from each other. So what you're doing is passing a second parameter to `alert()` which gets silently ignored.
What you want is possible this way:
alert((1,2));
The extra brackets form a parameter on their own; inside them you can use the comma as an operator.
Problem
MDN claims that: The comma operator evaluates both of its operands (from left to right) and returns the value of the second operand. However, when I tried running `<script> alert(1, 2); </script>`, it shows a "1" instead of a "2". Am I misunderstanding something?