Find if two arrays are repeated in array and then select them
arrays, javascript, jquery, multidimensional-array, object
Solution
You could take a `Map` with stringified arrays and count, then filter by count and restore the arrays.
var array = [[1, 17], [1, 17], [1, 17], [2, 12], [5, 9], [2, 12], [6, 2], [2, 12]],
result = Array
.from(array.reduce(
(map, array) =>
(json => map.set(json, (map.get(json) || 0) + 1))
(JSON.stringify(array)),
new Map
))
.filter(([, count]) => count > 2)
.map(([json]) => JSON.parse(json));
console.log(result);
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Filter with a map at wanted count.
var array = [[1, 17], [1, 17], [1, 17], [2, 12], [5, 9], [2, 12], [6, 2], [2, 12]],
result = array.filter(
(map => a =>
(json =>
(count => map.set(json, count) && !(2 - count))
(1 + map.get(json) || 1)
)
(JSON.stringify(a))
)
(new Map)
);
console.log(result);
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Unique!
var array = [[1, 17], [1, 17], [1, 17], [2, 12], [5, 9], [2, 12], [6, 2], [2, 12]],
result = array.filter(
(s => a => (j => !s.has(j) && s.add(j))(JSON.stringify(a)))
(new Set)
);
console.log(result);
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Problem
I have multiple arrays in a main/parent array like this: ``` var array = [[1, 17], [1, 17], [1, 17], [2, 12], [5, 9], [2, 12], [6, 2], [2, 12]]; ``` here are the array's for simpler reading: ``` [1, 17] [1, 17] [1, 17] [2, 12] [5, 9] [2, 12] [6, 2] [2, 12] [2, 12] ``` I want to select the arrays that are repeated 3 or more times (> 3) and assign it to a variable. So in this example, `var repeatedArrays` would be `[1, 17]` and `[2, 12]`. So this should be the final result: ``` console.log(repeatedArrays); >>> [[1, 17], [2, 12]] ``` I found something similar here but it uses underscore.js and lodash. How could I it with javascript or even jquery (if need be)?