How to search filenames by regex with "find"
bash, unix
Solution
find /home/test -regextype posix-extended -regex '^.*test\.log\.[0-9]{4}-[0-9]{2}-[0-9]{2}\.zip' -mtime +3
- `-name` uses globular expressions, aka wildcards. What you want is `-regex`
- To use intervals as you intend, you need to tell `find` to use Extended Regular Expressions via the `-regextype posix-extended` flag
- You need to escape out the periods because in regex a period has the special meaning of any single character. What you want is a literal period denoted by `\.`
- To match only those files that are greater than 3 days old, you need to prefix your number with a `+` as in `-mtime +3`.
Proof of Concept
$ find . -regextype posix-extended -regex '^.*test\.log\.[0-9]{4}-[0-9]{2}-[0-9]{2}\.zip'
./test.log.1234-12-12.zip
Problem
I was trying to find all files dated and all files 3 days or more ago. ``` find /home/test -name 'test.log.\d{4}-d{2}-d{2}.zip' -mtime 3 ``` It is not listing anything. What is wrong with it?