How to make round corners to both inside of a box and its border?
css, rounded-corners
Solution
Inner border calculations
First, you'll need to remove `-vendor-background-clip: padding-box` or set them to `border-box` the default in order to achieve the inner border radius.
The inner border radius is calculated as the difference of the outer border radius (`border-radius`) and the border width (`border-width`) such that
`inner border radius = outer border radius - border width`
Whenever the `border-width` is greater than the `border-radius`, the inner border radius is negative and you get some awkward inverted corners. Currently, I don't believe there is a property for adjusting the `inner-border-radius`, so you'll need to calculate it manually.
In your case:
`inner border radius = 6px - 5px = 1px`
Your new CSS should be:
.radius-all { border-radius: 6px; -moz-border-radius: 6px; -webkit-border-radius: 6px; }
.template-bg { background: #FFF; }
.template-border { border: 5px solid rgba(255, 255, 255, 0.2); }
Simply subtract the `border-radius` (6px) values from the `border-width` value (5px) in order to achieve your desired inner-border-radius:
Code that works for me
Tested on Firefox 3.x, Google Chrome, and Safari 5.0
.radius-all { border-radius: 10px; -moz-border-radius: 10px; -webkit-border-radius: 10px; }
.template-bg { background: #FFF; }
.template-border { border: 5px solid rgba(0, 0, 0, 0.2); } /* Note that white on white does not distinguish a border */
Adding color overlays in JavaScript
<script type="text/javascript">
var bodyBgColor = document.getElementsByTagName('body')[0].style.backgroundColor;;
// insert opacity decreasing code here for hexadecimal
var header = document.getElementsByTagName('header')[0];
header.style.backgroundColor = bodyBgColor;
</script>
I'm not entirely sure how to do hexadecimal arithmetic in JavaScript but I'm sure you can find an algorithm in Google.
Applying General Borders
Are you using a separate box `<div>` for your border through its `background` property? If so, you'll need to apply `border-radius` and its vendor specific properties on both the border box and the inner box:
<div id="border-box" style="border-radius: 5px;">
<div id="inner-box" style="border-radius: 5px;">
</div>
</div>
A much more efficient way would simply have the inner-box manage its own border:
<div id="inner-box" style="border: 4px solid blue; border-radius: 5px">
<!-- Content -->
</div>
CSS-wise, you could just declare a `.rounded-border` class and apply it to every box that will have rounded borders:
.rounded-borders {
border-radius: 5px;
-moz-border-radius: 5px;
-webkit-border-radius: 5px;
-khtml-border-radius: 5px;
}
And apply the class to any boxes that will have rounded borders:
<div id="border-box" class="rounded-borders">
<div id="inner-box" class="rounded-borders">
</div>
</div>
For a single box element, you'll still be required to declare the border size in order to be shown:
<style type="text/css">
#inner-box { border: 4px solid blue; }
</style>
<div id="inner-box" class="rounded-borders">
</div>
Problem
I guess the title is kind of hard to understand, so I'll explain. I am trying to achieve this effect: (a box which has rounded corners and its border, which also has rounded borders). I've managed to do this, by using the `background-clip` property: (rounded corners for border but not for inner box) The question is, how can I achieve rounded corners for the inner box? Thank you! EDIT The HTML I am using: ``` <header class="body template-bg template-border radius-all"> <nav> <ul> <li><a href="#">Link 1</a></li> <li><a href="#">Link 2</a></li> <li><a href="#">Link 3</a></li> <li><a href="#">Link 4</a></li> </ul> </nav> </header> ``` And the CSS: ``` .radius-all { border-radius: 10px; -moz-border-radius: 10px; -webkit-border-radius: 10px; } .template-bg { background: #FFF; -moz-background-clip: padding; -webkit-background-clip: padding; background-clip: padding-box; } .template-border { border: 5px solid rgba(255, 255, 255, 0.2); } ```