How to repeatedly execute a function every x seconds?
python, timer
Solution
If your program doesn't have a event loop already, use the sched module, which implements a general purpose event scheduler.
import sched, time
def do_something(scheduler):
# schedule the next call first
scheduler.enter(60, 1, do_something, (scheduler,))
print("Doing stuff...")
# then do your stuff
my_scheduler = sched.scheduler(time.time, time.sleep)
my_scheduler.enter(60, 1, do_something, (my_scheduler,))
my_scheduler.run()
If you're already using an event loop library like `asyncio`, `trio`, `tkinter`, `PyQt5`, `gobject`, `kivy`, and many others - just schedule the task using your existing event loop library's methods, instead.
Problem
I want to repeatedly execute a function in Python every 60 seconds forever (just like an NSTimer in Objective C or setTimeout in JS). This code will run as a daemon and is effectively like calling the python script every minute using a cron, but without requiring that to be set up by the user. In this question about a cron implemented in Python, the solution appears to effectively just sleep() for x seconds. I don't need such advanced functionality so perhaps something like this would work ``` while True: # Code executed here time.sleep(60) ``` Are there any foreseeable problems with this code?