Post-increment and pre-increment within a 'for' loop produce same output
c, c++, for-loop, operator-precedence
Solution
After evaluating `i++` or `++i`, the new value of `i` will be the same in both cases. The difference between pre- and post-increment is in the result of evaluating the expression itself.
`++i` increments `i` and evaluates to the new value of `i`.
`i++` evaluates to the old value of `i`, and increments `i`.
The reason this doesn't matter in a for loop is that the flow of control works roughly like this:
- test the condition
- if it is false, terminate
- if it is true, execute the body
- execute the incrementation step
Because (1) and (4) are decoupled, either pre- or post-increment can be used.
Problem
The following for loops produce identical results even though one uses post increment and the other pre-increment. Here is the code: ``` for(i=0; i<5; i++) { printf("%d", i); } for(i=0; i<5; ++i) { printf("%d", i); } ``` I get the same output for both 'for' loops. Am I missing something?