Laravel - Type error: Too few arguments?

laravel, laravel-5, laravel-5.4, php

Solution

If you are calling createList() by yourself so you will need to pass both parameters by yourself. You can bind something with Plan but still if you will call something not Laravel, then you will be responsible to pass that function parameters.

This type hinting only works if Laravel is calling that function. So you need to call these functions through Laravel.

If you are trying to automatically injecting in a class's constructor, you can simply do this:

$service = $this->app->make('App\Plan\todoservice');

or

$service = App::make('App\Plan\todoservice');

or

$service = resolve('App\Plan\todoservice');

But this will only work for Constructors. Please note that you can also provide parameters as next arguments of `make()` or `resolve()` function.

In fact, different methods can also be called that way.

You can simply do:

    $service = App::make('App\Plan\todoservice');
    $container->call([$service, 'createList'], ['request' => $request] );

Here `$container` is object of `Illuminate\Contracts\Container\Container`.

Problem

I get an error: Type error: Too few arguments I thought Laravel do some magic to if arguments is not fully passed? For example: In the Controller I have: ``` public function create(CreateRequest $request) { return $this->todoService->createList($request); } ``` In the `todoService` class: ``` use App\Plan class todoService { public function createList($request, Plan $plan) { // } } ``` As you can see I did not pass `Plan` class object. Do I have to bind or something?

Original source