Is there a way to create to use CreateSpyObj to create a spy of all methods in a class?

Question

I'm writing unit tests for my Angular app and I'm learning about how to use spies. Currently, every service that my component uses, I have to write something like this ``` let fakeMyService = jasmine.createSpyObj('fakeMyService', ['method1', 'method2']); fakeMyService.method1.and.returnValue(Observable.of()); fakeMyService.method2.and.returnValue(Observable.of()); TestBed.configureTestingModule({ declarations: [MyComponent], providers: [ { provide: MyService, useValue: fakeMyService } ] }).compileComponents(); ``` Although this works, it doesn't seem like the best way to set up my spies. For one, I have to type every single function in MyService that I want to put spies in. Secondly, it's not strongly typed. So if I ever change the name, I won't know immediately and also then, I'll have to update it in every place. Is there some sort of way where I can just specify the class and it'll automatically just return me a fake class with spies for all the methods? So something like this ```…

Accepted Answer

Try using the new `spyOnAllFunctions` feature:

```
let fakeMyService = spyOnAllFunctions(MyService);
```

be aware that this is a new feature and it's available only in the latest 3.x version of Jasmine.

Also be aware that this feature is not yet present in the current typing (@types/jasmine). There is a feature request about it here.

Is there a way to create to use CreateSpyObj to create a spy of all methods in a class?

Solution

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