finding type, for which is_constructible holds
c++, c++11, template-meta-programming, templates
Solution
First, some metaprogramming toys:
template<class Tag>
using type_t = typename Tag::type;
template<class T> struct tag_t{using type=T; constexpr tag_t(){}};
template<class T> constexpr tag_t<T> tag{};
template<class...Tuples>
using cat_tuples = decltype(std::tuple_cat( std::declval<Tuples>()... ));
template<template<class...>class Z, class Tuple, class=void>
struct filter;
template<template<class...>class Z, class Tuple>
using filter_t = type_t<filter<Z,Tuple>>;
template<template<class...>class Z>
struct filter<Z, std::tuple<>,void>:tag_t<std::tuple<>>{};
template<template<class...>class Z, class T0, class...Ts>
struct filter<Z, std::tuple<T0, Ts...>, std::enable_if_t<Z<T0>::value>>:
tag_t<
cat_tuples<
std::tuple<T0>,
filter_t<Z, std::tuple<Ts...>>
>
>
{};
template<template<class...>class Z, class T0, class...Ts>
struct filter<Z, std::tuple<T0, Ts...>, std::enable_if_t<!Z<T0>::value>>:
filter<Z, std::tuple<Ts...>>
{};
Now we solve your problem:
template<class...Args>
struct is_constructible_test {
template<class T>
using result=std::is_constructible<T,Args...>;
};
template<class Tuple, class...Args>
using all_constructible_t = filter_t<is_constructible_test<Args...>::template result, Tuple>;
template<class Tuple, class...Args>
using first_constructible = std::tuple_element_t<0, all_constructible_t<Tuple,Args...>>;
Test code:
struct bob {
bob( int, int, int ) {}
};
template<std::size_t>
struct alice {
alice(int) {}
};
int main() {
using is_alice = first_constructible<std::tuple<std::string, bob, alice<1>, alice<2>, int>, int>;
static_assert( std::is_same<is_alice, alice<1>>::value, "works" );
}
live example.
C++14, but just for `_t` aliases. replace `std::foo_t<blah>` with `typename std::foo<blah>::type`.
What I did was find every constructible type, then grabbed the first one. Filter is a simple concept I had lying around, and it was easier than writing "get first that passes test", as filter followed by get first unconditional is logically the same (if a bit more expensive).
You could modify `filter` above to "short out" and return instead of concatinating with tail when the test passes:
template<template<class...>class Z, class Tuple, class=void>
struct search;
template<template<class...>class Z, class Tuple>
using search_t = type_t<search<Z,Tuple>>;
template<template<class...>class Z>
struct search<Z, std::tuple<>,void>{};
template<template<class...>class Z, class T0, class...Ts>
struct search<Z, std::tuple<T0, Ts...>, std::enable_if_t<Z<T0>::value>>:
tag_t<T0>
{};
template<template<class...>class Z, class T0, class...Ts>
struct search<Z, std::tuple<T0, Ts...>, std::enable_if_t<!Z<T0>::value>>:
search<Z, std::tuple<Ts...>>
{};
and replace the `first_constructible` template with:
template<class Tuple, class...Args>
using first_constructible = search_t<is_constructible_test<Args...>::template result, Tuple>;
live example 2.
I could probably use utility functions like you did that interacts with Tuples rather than specializing, and there would be advantages.
One issue I see with yours is that `get<>` returns a reference, not a value. `std::tuple_element_t` might be a better plan.
Problem
I was playing around with templates and was trying to implement following helper. ``` first_constructible<Types..., Args...>::type ``` which would return first type of `Types` which is constructible from `Args...`. First problem obviously is having two parameter packs in `struct`, so I changed usage to ``` first_constructible<std::tuple<Types...>, Args...>::type ``` I've implemented it by splitting tuple types as first and rest, checked using `std::is_constructible` and recursed if neccessary. ``` template<typename T> struct pop_front_tuple { template<typename U, typename... Us> static std::tuple<Us...> impl(std::tuple<U, Us...>); using type = decltype(impl(std::declval<T>())); // std::tuple with removed first type }; template<typename Tuple, typename... Args> struct first_constructible { using first_type = decltype(std::get<0>(std::declval<Tuple>())); using type = typename std::conditional < std::is_constructible<first_type, Args...>::value, first_type, typename first_constructible<typename pop_front_tuple<Tuple>::type, Args...>::type >::type; }; // end of recursion template<typename... Args> struct first_constructible<std::tuple<>, Args...> { using type = void; }; ``` but it for some reason does not work. I.e ``` first_constructible<std::tuple<std::string, int>, std::string>::type a = ""; // works, a is std::string first_constructible<std::tuple<std::string, int>>::type a = ""; // fails, error: variable or field 'a' declared void first_constructible<std::tuple<std::string, int>, std::string::size_type, std::string::value_type> // fails, same error ``` I don't know where my mistake is. `std::is_constructible<std::string>::value` and `std::is_constructible<std::string, std::string::size_type, std::string::value_type>::value` are true. Coliru link