Remove from array if not present in another array

arrays, javascript

Solution

You can iterate over `idsToCheck` using `Array.prototype.filter()` to filter out all ids which are not in `allowedIds`. For example:

const checkedIds = idsToCheck.filter(id => allowedIds.includes(id));

Note: using ES6 features: `arrow functions` and `Array.prototype.includes()`. To use it in older browsers check for compatibility.

Here is an alternative implementation with better browser compatiblity:

var checkedIds = idsToCheck.filter(function(id) {
  return allowedIds.indexOf(id) > -1;
});

Problem

``` var allowedIds = [1000, 1001, 1002, 1003, 1004]; var idsToCheck = [1000, 1001, 1005, 1006]; ``` I'm looking to find a way to remove 1005 & 1006 from arrayToCheck as those ids are not in the allowedIds array any help would be appreciated. thanks!

Original source