How to invert a grep expression
grep, linux, regex
Solution
Use command-line option `-v` or `--invert-match`,
ls -R |grep -v -E .*[\.exe]$\|.*[\.html]$
Problem
The following grep expression successfully lists all the .exe and .html files in the current directory and sub directories. ``` ls -R |grep -E .*[\.exe]$\|.*[\.html]$ ``` How do I invert this result to list those that aren't a .html or .exe instead. (That is, `!=`.)