Finding average value in an array
arrays, php
Solution
Your `for` loop is counterproductive here. You're already using almost all the built-in functions you need to get the values you want, but with the `for` loop, you're using them many more times than necessary. All you need is:
$max = max($number);
$min = min($number);
$avg = array_sum($number) / count($number);
Problem
I am trying to find the minimum, maximum and average value in a number array: I have the following code below: ``` $number = array(15,20,100,10,25,30); for ($i=0; $i<count($number); $i++){ //Find maximum number by max function. if ($number[$i] == max($number)){ //Print maximum number. $max = $number[$i]; } //Find minimum number by min function. elseif ($number[$i] == min($number)) { //Print minimum number. $min = $number[$i]; } //Find the average else ($number[$i] == avg($number)){ //Print average number $avg =$number[$i]; } } echo "min value is $min <br/>"; echo "max value is $max <br/>"; echo "average value is $avg </br>"; ``` It seems to be giving me a syntax error on the average part. Please kindly help.