Creating Time Series from Pandas DataFrame

Question

I have a dataframe with various attributes, including one datetime column. I want to extract one of the attribute columns as a time series indexed by the datetime column. This seemed pretty straightforward, and I can construct time series with random values, as all the pandas docs show.. but when I do so from a dataframe, my attribute values all convert to NaN. Here's an analogous example. ``` df = pd.DataFrame({'a': [0,1], 'date':[pd.to_datetime('2017-04-01'), pd.to_datetime('2017-04-02')]}) s = pd.Series(df.a, index=df.date) ``` In this case, the series will have correct time series index, but all the values will be NaN. I can do the series in two steps, as below, but I don't understand why this should be required. ``` s = pd.Series(df.a) s.index = df.date ``` What am I missing? I assume it has to do with series references, but don't understand at all why the values would go to NaN. I am also able to get it to work by copying the index column. ``` s = pd.Series(df.a, df.date.copy())…

Accepted Answer

The problem is that `pd.Series()` is trying to use the values specified in `index` to select values from the dataframe, but the date values in the dataframe are not present in the index.

You can set the index to the date column and then select the one data column you want. This will return a series with the dates as the index

```
import pandas as pd

df = pd.DataFrame({'a': [0,1], 'date':[pd.to_datetime('2017-04-01'),
                                       pd.to_datetime('2017-04-02')]})    
s = df.set_index('date')['a']
```

Examining `s` gives:

```
In [1]: s
Out[1]: 
date
2017-04-01    0
2017-04-02    1
Name: a, dtype: int64
```

And you can confirm that `s` is a `Series`:

```
In [2]: isinstance(s, pd.Series)
Out[2]: True
```

Creating Time Series from Pandas DataFrame

Solution

Problem