Regex newline and whitespace in golang

Question

I was trying to match the below string with a regex and get some values out of it. ``` /system1/sensor37 Targets Properties DeviceID=37-Fuse ElementName=Power Supply OperationalStatus=Ok RateUnits=Celsius CurrentReading=49 SensorType=Temperature HealthState=Ok oemhp_CautionValue=100 oemhp_CriticalValue=Not Applicable ``` Used the below regex for that ``` `/system1/sensor\d\d .* .* \s*DeviceID=(?P.*) .* .* .* \s*CurrentReading=(?P\d*) \s*SensorType=Temperature \s*HealthState=(?P.*) ` ``` Now my question is: Is there a better way to do it? I explicitly mentioned each new line and white space group in the string. But can I just say `/system.sensor\d\d.*DeviceID=(?P.*) *.` (It didn't work for me, but I believe there should be a way to it.)

Accepted Answer

By default `.` does not match newlines. To change that, use the `s` flag:

```
(?s)/system.sensor\d\d.*DeviceID=(?P<sensor>.*)
```

From: RE2 regular expression syntax reference

`(?flags)` set flags within current group; non-capturing `s` - let `.` match `
` (default false)

Regex newline and whitespace in golang

Solution

Problem