How to set delay in Android onClick function

Question

) I'm in a process of creating a memory game. My problem is that whenever i click for the second time, i can't even see toggled button. To be clear - first click toggles the togglebutton, so i can see the number it holds, the second click on a different togglebutton is suposed to toggle it, show me the number and then proceed to either set a score +1 if numbers are the same, or reverse them back again if they're different. Below is the code that i use as my onClick function, i've been thinking about putting some kind of sleep or delay function somwhere in the second "if block" - (if(klikniecia ==2)). Any help on this topic would be appreciated. ``` public void onClick(View view) { for (int i = 0; i < karta.length; i++){ if (view == karta[i]){ karta[i].setEnabled(false); klikniecia++; if (klikniecia == 1){ kartaID[0]=i; kartaWartosc[0]=listaKart.get(i); } if (klikniecia == 2){ kartaID[1]=i; kartaWartosc[1]=listaKart.get(i); //i think, about setting a delay here, so i can see both of th…

Accepted Answer

Instead of sleeping in the onclick, you could post a delayed message to a handler (with associated runnable) and have it update the UI. Obviously fit this into the design of your app and make it work, but the basic idea is this:

```
//Here's a runnable/handler combo
private Runnable mMyRunnable = new Runnable()
{
    @Override
    public void run()
    {
       //Change state here
    }
 };
```

Then from onClick you post a delayed message to a handler, specifying that runnable to be executed.

```
Handler myHandler = new Handler();
myHandler.postDelayed(mMyRunnable, 1000);//Message will be delivered in 1 second.
```

Depending on how complicated your game is, this might not be exactly what you want, but it should give you a start.

How to set delay in Android onClick function

Solution

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