std::bind overload resolution

Question

The following code works fine ``` #include using namespace std; using namespace std::placeholders; class A { int operator()( int i, int j ) { return i - j; } }; A a; auto aBind = bind( &A::operator(), ref(a), _2, _1 ); ``` This does not ``` #include using namespace std; using namespace std::placeholders; class A { int operator()( int i, int j ) { return i - j; } int operator()( int i ) { return -i; } }; A a; auto aBind = bind( &A::operator(), ref(a), _2, _1 ); ``` I have tried playing around with the syntax to try and explicitly resolve which function I want in the code that does not work without luck so far. How do I write the bind line in order to choose the call that takes the two integer arguments?

Accepted Answer

You need a cast to disambiguate the overloaded function:

```
(int(A::*)(int,int))&A::operator()
```

std::bind overload resolution

Solution

Problem