Kill or terminate subprocess when timeout?
kill, python, signals, subprocess, timeout
Solution
You could do something like this:
import subprocess as sub
import threading
class RunCmd(threading.Thread):
def __init__(self, cmd, timeout):
threading.Thread.__init__(self)
self.cmd = cmd
self.timeout = timeout
def run(self):
self.p = sub.Popen(self.cmd)
self.p.wait()
def Run(self):
self.start()
self.join(self.timeout)
if self.is_alive():
self.p.terminate() #use self.p.kill() if process needs a kill -9
self.join()
RunCmd(["./someProg", "arg1"], 60).Run()
The idea is that you create a thread that runs the command and to kill it if the timeout exceeds some suitable value, in this case 60 seconds.
Problem
I would like to repeatedly execute a subprocess as fast as possible. However, sometimes the process will take too long, so I want to kill it. I use signal.signal(...) like below: ``` ppid=pipeexe.pid signal.signal(signal.SIGALRM, stop_handler) signal.alarm(1) ..... def stop_handler(signal, frame): print 'Stop test'+testdir+'for time out' if(pipeexe.poll()==None and hasattr(signal, "SIGKILL")): os.kill(ppid, signal.SIGKILL) return False ``` but sometime this code will try to stop the next round from executing. Stop test/home/lu/workspace/152/treefit/test2for time out /bin/sh: /home/lu/workspace/153/squib_driver: not found ---this is the next execution; the program wrongly stops it. Does anyone know how to solve this? I want to stop in time not execute 1 second the time.sleep(n) often wait n seconds. I do not want that I want it can execute less than 1 second