How continue execute program after assertion in python?

Question

I am learning Exception in python and i have some doubt: Can we use any name as error in raise? like i have read when you use raise you have to define error type so can't i use any stringname as Error? like `SkienaError` or i have to keep in mind all the error types and have to use only those Error type names ? ``` a=int(input()) if a!=10: raise SkienaError else: print(a,"pp") ``` Second doubt is suppose i want user should input int but he input string so an assert pop up but i want program should continue without terminate and again ask for input until user give int type input , I don't want to use while loop here i want to know if it is possible with raise or assert in python ? like: ``` a=int(input()) assert type(a)==int print(a,"hello") ``` So if user give str type input then is it possible program keep giving error and asking new input until input type is int.

Accepted Answer

In order to make your own exception, you'll have to create it.

e.g.

```
class MyAppLookupError(LookupError):
'''raise this when there's a lookup error for my app'''
```

To continue execution after a thrown Exception, do it like this:

```
a = 5
try:
    assert a == 5
except AssertionError as e:
    print(e)
```

A `try` block will attempt to execute a block of code. If an exception occurs, it will execute the `except` block.

How continue execute program after assertion in python?

Solution

Problem