Determining calling line without macro
c++, c-preprocessor, macros
Solution
I would do the following:
#define PrintLine() PrintLine_(__LINE__)
void PrintLine_(int line) {
std::cout << "Line: " << line << std::endl;
}
I know that this doesn't completely remove the preprocessor, but it does move most of the logic into an actual function.
Problem
Is it possible to determine the line number that calls a function without the aid of a macro? Consider this code: ``` #include <iostream> #define PrintLineWithMacro() \ std::cout << "Line: " << __LINE__ << std::endl; // Line 4 void PrintLine() { std::cout << "Line: " << __LINE__ << std::endl; // Line 8 } int main(int argc, char **argv) { PrintLine(); // Line 13 PrintLineWithMacro(); // Line 14 return 0; } ``` which outputs the following: ``` Line: 8 Line: 14 ``` I understand why each prints what they do. I am more interested if it's possible to mimic the macro function without using a macro.