findFirst() for Java streams, but for n elements?
java, java-8, java-stream, lazy-evaluation
Solution
MyList.stream()
.filter(x -> predicate(x))
.limit(100)
Problem
I want to collect the first n elements from a stream, without iterating through the entire thing. Is there a standard method that does this? Ala ``` MyList.stream() .filter(x -> predicate(x)) .findFirstN(100) ``` would return a collection of up to 100 elements from the stream? My alternative is to evaluate the entire stream and then sample from the result, but that doesn't take advantage of the lazy evaluation inherent to streams.