strange backslash operator in C assignment
c, embedded, texas-instruments
Solution
Non-portable, implementation dependent, non-standard conforming code. It is anybody's guess what the original author has intended but "probably" means `size += size & 0x1`. That is: increment size by 1 in case size is odd (that is, least significant bit is 1).
Problem
What does following `0x0\1` mean in following code? I find this in an embedded C code: ``` uint16 size; ... size += (size & 0x0\1); ``` It's part of Texas Instruments released code. It compiles in IAR ARM IDE.