call 2 functions in a function

Question

The problem is as follows below: Write a function compose that takes two functions as argument, we call them `Fa` and `Fb`, and returns a function, `Fres`, that means that outdata from the other function is indata to the first, ex: `Fres(x) = Fa(Fb(x))`. run example: ``` >>> def multiply_five(n): ... return n * 5 ... >>> def add_ten(x): ... return x + 10 ... >>> composition = compose(multiply_five, add_ten) >>> composition(3) 65 >>> another_composition = compose(add_ten, multiply_five) >>> another_composition(3) 25 ``` So as I understand this if I send in 3 the function compose will take 3+10 = 13 after that send that result into the multiply function it will do: 13*5 witch is 65. this is the code I've written so far: ``` def multiply_five(n): return n*5 def add_ten(x): return x+10 def compose(func1, func2): def comp(arg): return func2(arg) return func1(comp(arg)) ``` I get compile error, and I've tried some different approaches: ``` Traceback (most recent call last): File "<pyshell#3…

Accepted Answer

You don't want to call either `func1` or `func2` yet; you just want to return a function that will call them both.

```
def compose(func1, func2):
    def _(*args, **kw):
        return func1(func2(*args, **kw))
    return _
```

You could also just use a `lambda` expression to create the composed function.

```
def compose(func1, func2):
    return lambda *args, **kw: func1(func2(*args, **kw))
```

call 2 functions in a function

Solution

Problem