What's the opposite of JavaScript's Math.pow?
algebra, javascript, math, polynomial-math
Solution
c = Math.log(a)/Math.log(b)
Problem
I'm having a mental block here, and algebra not really being my thing, can you tell me how to re-write the JavaScript code below to derive the variable, `c`, in terms of `a` and `b`?: ``` a = Math.pow(b, c); c = ? ``` Thanks!