JavaScript replace() method dollar signs
javascript, string
Solution
It’s because `$$` inserts a literal "`$`".
So, you need to use:
a = "aman/gupta";
a = a.replace("/", "$$$$"); // "aman$$gupta"
See the following special patterns:
Pattern Inserts
`$$` Inserts a "`$`".
`$&` Inserts the matched substring.
`$`` Inserts the portion of the string that precedes the matched substring.
`$'` Inserts the portion of the string that follows the matched substring.
`$`n Where n is a non-negative integer less than 100, inserts the _n_th parenthesized submatch string, provided the first argument was a RegExp object.
`$<`Name`>` Where Name is a capturing group name. If the group is not in the match, or not in the regular expression, or if a string was passed as the first argument to `replace` instead of a regular expression, this resolves to a literal (e.g., "`$<Name>`").
Problem
I have a string like `aman/gupta` and I want to replace it to `aman$$gupta` and for that I am using JavaScript `replace` method as follows: ``` let a = "aman/gupta" a = a.replace("/", "$") console.log(a) // 'aman$gupta' a = "aman/gupta" a = a.replace("/", "$$") console.log(a) // 'aman$gupta' a = "aman/gupta" a = a.replace("/", "$$$") console.log(a) // 'aman$$gupta' ``` Why are the 1st and 2nd case identical and I get the expected result when I use `$$$` instead of `$$`?