one if statement with unknown number of conditions python
if-statement, python
Solution
You can use a generator expression within `all()`:
if all(i == j for i, j in my_list): # use int(j) if 'j' is string and 'i' is integer.
# do something
Problem
I have a list of list that contains all the conditions that the if statement has to satisfy, but the problem is that the number of conditions stored into the list of list is unknown. For e.g., the list of list is like this: ``` my_list: [["A", "0"], ["B", "1"], ["C", "2"]] ``` so the if should be: ``` if A==0 and B==1 and C==2: #do-something else: pass ``` since I don't know the number of elements in the list of lists, I cannot do: ``` if my_list[0][0]==my_list[0][1] and my_list[1][0]==my_list[1][1] and my_list[2][0]==my_list[2][1]: #do-something else: pass ``` how do I solve this problem? A similar problem has been raised here but there is no a clear explanation/implementation of this problem. Thanks.