How to catch any method call on object in PHP?

interception, object, php

Solution

Taking your original `Foo` implementation you could wrap a `decorator` around it like this:

class Foo 
{
    public function bar() {
        echo 'foobar';
    }
}

class Decorator 
{
    protected $foo;

    public function __construct(Foo $foo) {
       $this->foo = $foo;
    }

    public function __call($method_name, $args) {
       echo 'Calling method ',$method_name,'<br />';
       return call_user_func_array(array($this->foo, $method_name), $args);
    }
}

$foo = new Decorator(new Foo());
$foo->bar();

Problem

I am trying to figure out how to catch any method called on an object in PHP. I know about the magic function `__call`, but it is triggered only for methods that do not exist on the called object. For example i have something like this: ``` class Foo { public function bar() { echo 'foobar'; } public function override($method_name,$method_args) { echo 'Calling method ',$method_name,'<br />'; $this->$method_name($method_args); //dirty, but working } } ``` And when i do this: ``` $foo = new Foo(); $foo->bar(); ``` I want this output: ``` Calling method bar foobar ``` instead of this one: ``` foobar ``` Is there any way how to do this? Help please :)

Original source