Using awk to print all columns from the nth to the last

Question

This line worked until I had whitespace in the second field: ``` svn status | grep '\!' | gawk '{print $2;}' > removedProjs ``` Is there a way to have `awk` print everything in `$2` or greater? (`$3`, `$4`.. until we don't have any more columns?) I'm doing this in a Windows environment with Cygwin.

Accepted Answer

Print all columns:

```
awk '{print $0}' somefile
```

Print all but the first column:

```
awk '{$1=""; print $0}' somefile
```

Print all but the first two columns:

```
awk '{$1=$2=""; print $0}' somefile
```

Using awk to print all columns from the nth to the last

Solution

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